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K = 10^(dB/20); π: R₁ = Z₀(K+1)/(K−1), R₂ = Z₀(K²−1)/(2K); T: R₁ = Z₀(K−1)/(K+1), R₂ = 2Z₀K/(K²−1); bridge: R₁ = Z₀(K−1), R₂ = Z₀/(K−1)
Calculate resistor pads from attenuation and matched impedance. Check dB power ratios, termination assumptions and resistor power dissipation.
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Use K = 10^(AdB/20); Pout/Pin = 10^(−AdB/10). Calculate resistor pads from attenuation and matched impedance. Check dB power ratios, termination assumptions and resistor power dissipation.
Sources: analog.com [1]
K = 10; Pout/Pin = 0.01. This is a calculated example under the model stated above; it is not a measured component specification.
dB, Ω, W. Convert prefixes before substituting values; keep the input and output units attached to every number.
Sources: analog.com [1]
The pad equations assume their stated terminations. A mismatched load changes attenuation and input impedance; the open-circuit voltage ratio is not the matched insertion loss.
Sources: analog.com [1]
Approximately, under matched conditions: transmitted power is 10^(−3/10) ≈ 50.12%. Check each resistor’s share and pulse rating rather than rating all resistors from total loss alone.
Sources: analog.com [1]
No. Package parasitics, PCB layout and resistor technology affect return loss and frequency response. Verify the assembled network over the required band.
Sources: analog.com [1]
Answers use the stated model and units. Examples are calculated values, not measurements or component ratings.
